怎样破解ms sql server 2000的加密存储过程?(300分)

就用dhl2001的吧!他写的比较全面一些,是一个可行的办法
 
dhl2001的算法原理上是对的,但无法解密大于4000字的加密对象。
 
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11 0x906D
用dhl2001的算法出现以上的,是什么意思啊,怎么用它解啊
 
你这个好象超过了40000个字符,无法解决

照上面的改一下,变成无限制的就行了。
 
不对啊
我的没有超过4000吧?
是如下:
SET QUOTED_IDENTIFIER ON
GO
SET ANSI_NULLS ON
GO

ALTER Proc DeleteCxm
As
Declare @gh Varchar(6)
Declare @rq Varchar(8)
Declare cxm Cursor For Select abm_gh,abm_rq From abm_mstr Where abm_zt In ('1','2')
Open cxm
Fetch Next From cxm Into @gh,@rq
While @@Fetch_Status=0
Begin
If Exists(Select * From cxm_mstr Where cxm_zt='4' And cxm_gh=@gh And cxm_rq=Convert(Smalldatetime,@rq))
Update abm_mstr Set abm_zt='3' Where abm_gh=@gh And abm_rq=@rq
Fetch Next From cxm Into @gh,@rq
End
Close cxm
Deallocate cxm

GO
SET QUOTED_IDENTIFIER OFF
GO
SET ANSI_NULLS ON
GO
后我加密再解密就出现以上的了
 
试了一下,确实没有解开。我看看怎么回事
 
关注,学习
 
上面这些代码,根本不行。。。。:(
 
对啊, 我昨天测试了下午;都不行;
不过dhl2001答应在查看是怎以回事

希望能解决这个问题
 
你这条语句加密后是11条记录,也就是大于40000个字符。
加了一个@sql11后修改成功,
一会做个无限制的!
 
谢谢你,幸苦了
 
在存储过程中解决这个问题 不好解决。
写个程序去解决吧,
这个算法很简单的。
 
唉 dhl2001的算法很巧妙 可惜有点美中不足阿

那就是每用一次 就要把被解密的过程修改一次 虽然不影响使用

但是感觉有点不是很完美 nina老兄 有没更好的法子 嘿嘿

 
我想大概不可能吧~~ 。要是能轻易就破的话,ms不是太丢面子了。
关注,学习
 
只能解一些简单的吧!
 
大家拿出点程序员的职业精神
自已动手用Delphi做个程序不就结了


 
无限制版
直接写在存储过程里,我还没写出什么好招。

有两个方法,一写一个客户端,那不是再简单不过的事。
二,写一个sqlserver扩展存储过程,有人会写吗?我不太熟悉C

 
dhl2001 你好
你提供的这个算法 在寻找进行xor操作的字符串的时候 将原存储过程修改了一次
虽然说事后可以将该过程再改回原样 但是别人据此可以看出该过程是否被解密过
嘿嘿~~ 不知兄台注意到这点没有

我另外将开300分的贴子 希望笑纳哈
 
对于T-SQL,不能处理大于4000字的串,所欲要完全破解加密对象只能用其他的开发语言来开发破解程序;对于将原存储过程修改的问题,很很很简单,
begin transaction.....rollback
 
樓上: what's meanse this 16x?


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11 0xE1A8
 
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