SQL> select * from emp;
EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
--------- ---------- --------- --------- ---------- --------- --------- ---------
7369 SMITH CLERK 7902 17-12る-80 800 20
7499 ALLEN SALESMAN 7698 20-2る -81 1600 300 30
7521 WARD SALESMAN 7698 22-2る -81 1250 500 30
7566 JONES MANAGER 7839 02-4る -81 2975 20
7654 MARTIN SALESMAN 7698 28-9る -81 1250 1400 30
7698 BLAKE MANAGER 7839 01-5る -81 2850 30
7782 CLARK MANAGER 7839 09-6る -81 2450 10
7788 SCOTT ANALYST 7566 19-4る -87 3000 20
7839 KING PRESIDENT 17-11る-81 5000 10
7844 TURNER SALESMAN 7698 08-9る -81 1500 0 30
7876 ADAMS CLERK 7788 23-5る -87 1100 20
7900 JAMES CLERK 7698 03-12る-81 950 30
7902 FORD ANALYST 7566 03-12る-81 3000 20
7934 MILLER CLERK 7782 23-1る -82 1300 10
14 rows selected. 1 select ename,max,b.deptno
SQL>
1 select ename,max,deptno
2 from
3 (select deptno,max(sal) max from emp group by deptno) a,
4 emp b
5 where a.deptno=b.deptno
6* and b.sal=a.max
SQL> /
ENAME MAX DEPTNO
---------- --------- ---------
KING 5000 10
SCOTT 3000 20
FORD 3000 20
BLAKE 2850 30
//这个答案你是不是楼上所需求的?你的分别忘了给我啊!