使用NMSMTP发送邮件,如何过服务器效验这一关?(100分)

  • 主题发起人 主题发起人 myyzg
  • 开始时间 开始时间
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myyzg

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现在许多邮件服务器都要求用户在发送邮件时进行效验,如果选择了,报以下错误,如何处理:
--------------------------
Debugger Exception Notification
---------------------------
Project Project1.exe raised exception class Exception with message '553 You
are not authorized to send mail as <MAIL FROM:<mypost@263.net>>,
authentication is required
'. Process stopped. Use Step or Run to continue.
---------------------------
OK Help
---------------------------
 
可惜我只会C++Builder的,原理一样。
http://nowcan.yeah.net
编程技术-》BCB-》网络
里面找。
 
const
BaseTable:string='ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/=';

var
function DecodeBase64(Source:string):string; //解码函数
function FindInTable(CSource:char):integer; //
function EncodeBase64(Source:string):string; //编码函数
function FindInTable(CSource:char):integer;
begin
result:=Pos(string(CSource),BaseTable)-1;
end;
////
function DecodeBase64(Source:string):string;
var
SrcLen,Times,i:integer;
x1,x2,x3,x4,xt:byte;
begin
result:='';
SrcLen:=Length(Source);
Times:=SrcLen div 4;
for i:=0 to Times-1 do
begin
x1:=FindInTable(Source[1+i*4]);
x2:=FindInTable(Source[2+i*4]);
x3:=FindInTable(Source[3+i*4]);
x4:=FindInTable(Source[4+i*4]);
x1:=x1 shl 2;
xt:=x2 shr 4;
x1:=x1 or xt;
x2:=x2 shl 4;
result:=result+chr(x1);
if x3= 64 then break;
xt:=x3 shr 2;
x2:=x2 or xt;
x3:=x3 shl 6;
result:=result+chr(x2);
if x4=64 then break;
x3:=x3 or x4;
result:=result+chr(x3);
end;
end;
/////
function EncodeBase64(Source:string):string;
var
Times,LenSrc,i:integer;
x1,x2,x3,x4:char;
xt:byte;
begin
result:='';
LenSrc:=length(Source);
if LenSrc mod 3 =0 then Times:=LenSrc div 3
else Times:=LenSrc div 3 + 1;
for i:=0 to times-1 do
begin
if LenSrc >= (3+i*3) then
begin
x1:=BaseTable[(ord(Source[1+i*3]) shr 2)+1];
xt:=(ord(Source[1+i*3]) shl 4) and 48;
xt:=xt or (ord(Source[2+i*3]) shr 4);
x2:=BaseTable[xt+1];
xt:=(Ord(Source[2+i*3]) shl 2) and 60;
xt:=xt or (ord(Source[3+i*3]) shr 6);
x3:=BaseTable[xt+1];
xt:=(ord(Source[3+i*3]) and 63);
x4:=BaseTable[xt+1];
end
else if LenSrc>=(2+i*3) then
begin
x1:=BaseTable[(ord(Source[1+i*3]) shr 2)+1];
xt:=(ord(Source[1+i*3]) shl 4) and 48;
xt:=xt or (ord(Source[2+i*3]) shr 4);
x2:=BaseTable[xt+1];
xt:=(ord(Source[2+i*3]) shl 2) and 60;
x3:=BaseTable[xt+1];
x4:='=';
end else
begin
x1:=BaseTable[(ord(Source[1+i*3]) shr 2)+1];
xt:=(ord(Source[1+i*3]) shl 4) and 48;
x2:=BaseTable[xt+1];
x3:='=';
x4:='=';
end;
result:=result+x1+x2+x3+x4;
end;
end;
procedure TForm1.NMSMTP1Connect(Sender: TObject);
begin
//////连接成功,下面用户认证过程
if nmsmtp1.ReplyNumber = 250 then
nmsmtp1.Transaction('auth login'); //开始认证
if nmsmtp1.ReplyNumber =334 then //返回值为334,让你输入用BASE64编码后的用户名
nmsmtp1.Transaction(EncodeBase64('aaaaa'));// 用户名aaaaa
if nmsmtp1.ReplyNumber =334 then // 返回值为334,让你输入用BASE64编码后的用户密码
nmsmtp1.Transaction(EncodeBase64('123456')); //密码为123456
if nmsmtp1.ReplyNumber =235 then
end;

你可以试一试。
 
用indy就可以了,很简单的。你试试看!
 
D5好像没得救,D6可以,用indy,D6本身有demo
 
D5用上面那段代码就可以了
 
多人接受答案了。
 
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