用api激活另一个程序里被禁用的按钮(50分)

怎么做 ？

一定要程序实现吗？<br>不用程序实现：拿eXeScope把button的属性改一下就行。

首先得到按钮handle，然后<br>BOOL EnableWindow(<br><br>&nbsp; &nbsp; HWND hWnd, // handle to window<br>&nbsp; &nbsp; BOOL bEnable // flag for enabling or disabling input<br>&nbsp; &nbsp;

sendmessage(

按照. 一个过客的思想，我编写了一个好程序，（没有实验）。<br>枚举所有窗口，发送设置Enable，呵呵，太霸道一些了，不知道是否游泳。<br>function EnumChildWindowsProc(hwnd: Integer; lparam: Longint): Boolean; stdcall;<br>begin<br>&nbsp; EnableWindow(hwnd,True);<br>&nbsp; InvalidateRgn(hwnd, 0, True);<br>&nbsp; Result := True; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; //终止循环<br>end;<br><br>procedure Call_Btn_Enable;<br>var<br>&nbsp; Window_Handle: Integer;<br>begin<br>&nbsp; Window_Handle := GetWindow(Application.Handle, GW_HWNDFIRST);<br>&nbsp; while Window_Handle &lt;&gt; 0 do<br>&nbsp; begin<br>&nbsp; &nbsp; if Window_Handle &lt;&gt; 0 then<br>&nbsp; &nbsp; begin<br>&nbsp; &nbsp; &nbsp; EnumChildWindows(Window_Handle, @EnumChildWindowsProc, 0);<br>&nbsp; &nbsp; end;<br>&nbsp; &nbsp; Window_Handle := GetWindow(Window_Handle, GW_HWNDNEXT);<br>&nbsp; end;<br>end;<br>

sendmessage(buttonhandle,BM_CLICK,0,0);

haha，有意思，这办法都有<br>不过我早就不用封菜单和按钮的办法来设置权限了，我把权限判断写在里面[^][^]

就是以后还得防着这招。哈哈

应该根据XX来设置按钮状态，而不是根据按钮状态来设置XX

我也真是的<br>明明知道只用一个api函数就行<br>那天竟也发了个帖子，结了吧

多人接受答案了。