如何获得选择的文件名称(20分)

E

erbbchen

Unregistered / Unconfirmed

GUEST, unregistred user!

• 2006-02-09

• #1

xlsFileName := OpenDialog1.FileName;

这样获得的是文件整个路径+文件名,我只想获得文件名称,该怎么做呢?

 

L

liyinwei

Unregistered / Unconfirmed

GUEST, unregistred user!

• 2006-02-09

• #2

xlsFileName := ExtractFileName(OpenDialog1.FileName);

 

Z

zylsoft

Unregistered / Unconfirmed

GUEST, unregistred user!

• 2006-02-09

• #3

xlsFileName := ExtractFileName(OpenDialog1.FileName);

 

雾

雾锁长河

Unregistered / Unconfirmed

GUEST, unregistred user!

• 2006-02-09

• #4

同意楼上的

 

T

tonyliu

Unregistered / Unconfirmed

GUEST, unregistred user!

• 2006-02-09

• #5

是的就是上面两位富翁说的那样

 

寒

寒战

Unregistered / Unconfirmed

GUEST, unregistred user!

• 2006-02-10

• #6

同意二楼和三楼的

 

S

SiWeiLiuLang

Unregistered / Unconfirmed

GUEST, unregistred user!

• 2006-02-10

• #7

僧多粥少拉

 

E

erbbchen

Unregistered / Unconfirmed

GUEST, unregistred user!

• 2006-02-10

• #8

接受答案了.