L
leo_aj
Unregistered / Unconfirmed
GUEST, unregistred user!
hi,everyone:
I Study in MIT. now i got the final project for this semester.
i like delphi very much, so like share the experience with you guys.
This project is about simulation. you can look the specification later. It is not
very easy actually, maybe for you not. now, for me i thought i finish 30%.
hope you can finish it soon(have to within two weeks).
i'll be glad to do with you .
if you choose it, or interest about it, i can send some handout about simulation.
Hints:
you can divide this wire into lots of pieces. and can creat a unit for piece, which
type is TPanel. create another for wire, which type is Tlist. so very piece is a items
of that wire(Twire).
ok, good lucky.
you can send me email (leo_aj@zfee.co.nz) if you need some help.
finally, i need your whole project.
NOTE: have to finish before 16/10/00
6D70 Introduction to Computer Science
Projects
Heated wire
Electric current flows through a piece of conductive wire of a given length and cross-section. The wire's ends are terminated with ideal heatsinks, always keeping the temperature at a given, fixed value. Assuming that no energy from the wire is radiated, the entire energy of the electric current is converted to heat and flows to the terminating heatsinks, according to the equation:
where:
k thermal conductivity of the wire material
l wire length
A wire cross-section
DT temperature difference
The resistivity of the wire material varies with temperature according to the formula:
where:
r resistivity of the wire material at temperature T
resistivity of the wire material at room temperature
a resistivity temperature coefficient
T the temperature of the material
room temperature = 293.15 K
Recall that the resistance of a piece of wire is given by:
where:
r resistivity of the wire material
l wire length
A wire cross-section
Recall also that, when a current I flows through a resistance R, the dissipated thermal power is given by:
Simulate the behaviour of the wire. Assume that a fixed DC voltage source is connected at the beginning of the simulation, when the wire is cold (i.e. its temperature equals the temperature of the heatsinks).
Allow the user to modify the following parameters:
Parameter Symbol Unit Range Default value
wire length Lwire m 0.05 - 1 0.1
wire cross-section Swire m2 10-8 - 10-6 10-7
wire material thermal conductivity Kwire W.(m.K)-1 20 - 450 393
wire material room temp. resistivity R0 W.m 1.65´10-6 - 5´10-5 1.78´10-6
wire material resistivity coefficient Awire K-1 0.002 - 0.006 0.00392
heatsink temperature Tsinks K 0 - 1000 293.15
voltage Vwire V 10-3 - 102 10-2
wire material melting point Tmelt K 600 - 3700 1356.15
An appropriate graphical representation, continuously showing the current distribution of temperatures along the wire, is required. This can be achieved by mapping temperature values to different colours.
One (spectacular) experiment you can conduct using this program may consist of adjusting the simulation parameters to demonstrate a situation when the middle section of the wire reaches melting point, at which moment the wire disintegrates and stops conducting.
I Study in MIT. now i got the final project for this semester.
i like delphi very much, so like share the experience with you guys.
This project is about simulation. you can look the specification later. It is not
very easy actually, maybe for you not. now, for me i thought i finish 30%.
hope you can finish it soon(have to within two weeks).
i'll be glad to do with you .
if you choose it, or interest about it, i can send some handout about simulation.
Hints:
you can divide this wire into lots of pieces. and can creat a unit for piece, which
type is TPanel. create another for wire, which type is Tlist. so very piece is a items
of that wire(Twire).
ok, good lucky.
you can send me email (leo_aj@zfee.co.nz) if you need some help.
finally, i need your whole project.
NOTE: have to finish before 16/10/00
6D70 Introduction to Computer Science
Projects
Heated wire
Electric current flows through a piece of conductive wire of a given length and cross-section. The wire's ends are terminated with ideal heatsinks, always keeping the temperature at a given, fixed value. Assuming that no energy from the wire is radiated, the entire energy of the electric current is converted to heat and flows to the terminating heatsinks, according to the equation:
where:
k thermal conductivity of the wire material
l wire length
A wire cross-section
DT temperature difference
The resistivity of the wire material varies with temperature according to the formula:
where:
r resistivity of the wire material at temperature T
resistivity of the wire material at room temperature
a resistivity temperature coefficient
T the temperature of the material
room temperature = 293.15 K
Recall that the resistance of a piece of wire is given by:
where:
r resistivity of the wire material
l wire length
A wire cross-section
Recall also that, when a current I flows through a resistance R, the dissipated thermal power is given by:
Simulate the behaviour of the wire. Assume that a fixed DC voltage source is connected at the beginning of the simulation, when the wire is cold (i.e. its temperature equals the temperature of the heatsinks).
Allow the user to modify the following parameters:
Parameter Symbol Unit Range Default value
wire length Lwire m 0.05 - 1 0.1
wire cross-section Swire m2 10-8 - 10-6 10-7
wire material thermal conductivity Kwire W.(m.K)-1 20 - 450 393
wire material room temp. resistivity R0 W.m 1.65´10-6 - 5´10-5 1.78´10-6
wire material resistivity coefficient Awire K-1 0.002 - 0.006 0.00392
heatsink temperature Tsinks K 0 - 1000 293.15
voltage Vwire V 10-3 - 102 10-2
wire material melting point Tmelt K 600 - 3700 1356.15
An appropriate graphical representation, continuously showing the current distribution of temperatures along the wire, is required. This can be achieved by mapping temperature values to different colours.
One (spectacular) experiment you can conduct using this program may consist of adjusting the simulation parameters to demonstrate a situation when the middle section of the wire reaches melting point, at which moment the wire disintegrates and stops conducting.
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