请问FOXPRO中的BITNOT和ASC函数在D5中对应的是哪个？ (50分)

B

bastek

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• 2002-01-30

• #1

请问FOXPRO中的BITNOT和ASC函数在D5中对应的是哪个？
THANK YOU!

 

D

dongberlin

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• 2002-01-30

• #2

可能是NOT和ORD

 

B

bastek

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• 2002-01-30

• #3

Nobody know? or 分太少？

 

Z

zhukewen

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• 2002-01-30

• #4

dongberlin说的对。
就是not和ord

 

B

bastek

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• 2002-01-30

• #5

但从我摘自《MSDN》
BITNOT function
See also
Returns a 16-bit binary number in which each bit is set to 1
only if the corresponding bit in binary number is 0. Otherwise,
the bit is set to 0.
Syntax
BITNOT(binary number)
Example
BITNOT(6)
Returns 65529. The 6 = 0...00110. Therefore, BITNOT(6) = 1...11001.
应该是将一整数返回一个十六进制的函数。

 

B

bastek

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• 2002-01-30

• #6

WHAT IS 将一整数返回一个十六进制的函数?

 

B

bastek

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• 2002-01-30

• #7

BITNOT 对应的是 inttohex ，对吗？

 

B

bastek

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• 2002-01-31

• #8

熟悉FOXPRO的朋友能给点意见吗？

 

L

libin06

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• 2002-02-09

• #9

其实你上面不是已经说的很清楚了吗，
BITNOT就是按位取反，就是not，不过要将值限定为Word，
Word(not 6) = 65529