出个题目吧(100分)

  • 主题发起人 妙兔无花
  • 开始时间

妙兔无花

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也就相当于数据结构课的一个大作业吧。比表达式运算复杂一些。
程序输入:X1,X2,...,Xn一共n个整数
程序输出:使用X1~X(n-1),通过四则运算得到目标整数Xn
这是一个通用要求的题目,当n=5的时候有一个特例是大家都熟悉“算二十四”
当然这个要更复杂一些。
至于实现的原理什么的就不用讨论得很细了,因为就是比较基础的穷举搜索
如果你有什么很别出心裁的实现,也欢迎提出来。
鼓励自己亲手编程实现这个题目,使用语言不限,要求程序的健壮性。
过几天我给出一个参照执行程序,如果你的程序在同一台机器上能够在
时间或者空间上胜过我给的参照程序,那就请给大家上一课,讲讲你的程序:)
注:1。首先运行结果要正确,并且和参照程序给出的最简化结果一样
2。时间比较是指程序运行速度的比较,参照程序打印出结果最后会给出运行时间
3。空间比较是指程序运行需要消耗的内存的比较,直观效果就看你的程序最多能
完成多少个数的四则运算搜索,我的参照程序最多也就求11个整数的四则运算
4。稍后我给出标准的输入测试数据和相应参照输出结果
 
第一组输入:4 4 10 15 18 60
即对4,4,10,15,18一共五个数进行四则运算求得60
 
参照程序如下:
_=_
_=_ Part 001 of 001 of file Arith.zip
_=_
begin
666 Arith.zip
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`
end
 
嗯,怎么看上去好象就是一大堆乱码啊?!
 
本来就是一堆乱码[:D]
 
你们不知道base64编码吗?
 
不会是病毒吧~
 
to 妙兔无花:我没有工具解您的压缩码,把原代码贴出来瞧瞧。
 
??
什么东西
 
把压缩编码保存为Arith.zip,用winzip就可以打开。。。
见鬼,怎么连base64编码都不知道呢。。。
 
打不开!
见鬼
 
打不开是你没弄对,多试试吧
 
我倒。这也是BASE64码!
 
好玩,因为不想考虑括号,所以计算过程顺序排列。[:)][:D][8D][:(][:(!][^][?]
program Project2;
{$APPTYPE CONSOLE}
uses
SysUtils;
label
StartReadCount;
var
iCount, iMax, i: Integer;
sTemp: string;
aParameters: array of Integer;
aParameterUsed: array of Boolean;
function ReadInteger(Hint: string): Integer;
var
sInteger: string;
bTestResult: Boolean;
begin
Result:= 0;
repeat
Write(Hint);
Readln(sInteger);
bTestResult:= True;
try
Result:= StrToInt(sInteger);
except
bTestResult:= False;
end;
bTestResult:= bTestResult and (Result>0)
until bTestResult;
end;

function GetResult(Aim, Level: Integer): string;
var
i: Integer;
s: string;
begin
Result:= '';
for i:=Low(aParameters) to High(aParameters)do
if not aParameterUsed
then
if (Level=iCount-1) and (aParameters=Aim)
then
Result:= IntToStr(aParameters)
else
begin
aParameterUsed:= True;
if Aim mod aParameters=0
then
begin
s:= GetResult(Aim div aParameters, Level+1);
if s<>''
then
begin
Result:= s+ #13#10+ '*'+ IntToStr(aParameters);
Break;
end;
end;
s:= GetResult(Aim* aParameters, Level+ 1);
if s<>''
then
begin
Result:= s+ #13#10+ '/'+ IntToStr(aParameters);
Break;
end;
s:= GetResult(Aim- aParameters, Level+ 1);
if s<>''
then
begin
Result:= s+ #13#10+ '+'+ IntToStr(aParameters);
Break;
end;
s:= GetResult(Aim+ aParameters, Level+ 1);
if s<>''
then
begin
Result:= s+ #13#10+ '-'+ IntToStr(aParameters);
Break;
end;
aParameterUsed:= False;
end;
end;
begin
iCount:= ReadInteger('请输入参数个数:');
iMax:= ReadInteger('请输入参数最大值:1..');
SetLength(aParameters, iCount);
SetLength(aParameterUsed, iCount);
for i:=Low(aParameters) to High(aParameters)do
begin
aParameters:= Random(iMax)+ 1;
aParameterUsed:= False;
end;
sTemp:= '';
for i:=Low(aParameters) to High(aParameters)do
sTemp:= sTemp+ IntToStr(aParameters)+ '/';
sTemp:= Copy(sTemp, 1, Length(sTemp)- 1);
Writeln('系统自动生成的参数:'+ sTemp);
aParameterUsed[High(aParameterUsed)]:= True;
sTemp:= GetResult(aParameters[iCount-1], 1);
if sTemp=''
then
Writeln('没有找到计算结果!')
else
Writeln('计算结果如下:'+ #13#10+ sTemp);
Readln;
end.
 
转贴CSDN算法版主starfish的源码,写的应该是很不错了:
#include <iostream>
#include <string>
#include <cmath>
using namespace std;
constdo
uble PRECISION = 1E-6;
const int COUNT_OF_NUMBER = 4;
const int NUMBER_TO_BE_CAL = 24;
double number[COUNT_OF_NUMBER];
string expression[COUNT_OF_NUMBER];
bool Search(int n)
{
if (n == 1) {
if ( fabs(number[0] - NUMBER_TO_BE_CAL) < PRECISION ) {
cout << expression[0] << endl;
return true;
} else
{
return false;
}
}
for (int i = 0;
i < n;
i++) {
for (int j = i + 1;
j < n;
j++) {
do
uble a, b;
string expa, expb;
a = number;
b = number[j];
number[j] = number[n - 1];
expa = expression;
expb = expression[j];
expression[j] = expression[n - 1];
expression = '(' + expa + '+' + expb + ')';
number = a + b;
if ( Search(n - 1) ) return true;

expression = '(' + expa + '-' + expb + ')';
number = a - b;
if ( Search(n - 1) ) return true;

expression = '(' + expb + '-' + expa + ')';
number = b - a;
if ( Search(n - 1) ) return true;

expression = '(' + expa + '*' + expb + ')';
number = a * b;
if ( Search(n - 1) ) return true;
if (b != 0) {
expression = '(' + expa + '/' + expb + ')';
number = a / b;
if ( Search(n - 1) ) return true;
}
if (a != 0) {
expression = '(' + expb + '/' + expa + ')';
number = b / a;
if ( Search(n - 1) ) return true;
}
number = a;
number[j] = b;
expression = expa;
expression[j] = expb;
}
}
return false;
}
void main()
{
for (int i = 0;
i < COUNT_OF_NUMBER;
i++) {
char buffer[20];
int x;
cin >> x;
number = x;
itoa(x, buffer, 10);
expression = buffer;
}
if ( Search(COUNT_OF_NUMBER) ) {
cout << "Success." << endl;
} else
{
cout << "Fail." << endl;
}
}
 
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