B beta Unregistered / Unconfirmed GUEST, unregistred user! 2002-11-20 #2 if AnsiPos('a', aString) > 0 then 有 a
傻 傻的惊动党 Unregistered / Unconfirmed GUEST, unregistred user! 2002-11-20 #4 用 if pos('a',字符串)=0 then 字符串中没 'a'
Z zw84611 Unregistered / Unconfirmed GUEST, unregistred user! 2002-11-20 #5 if pos('a',str)=0 then ShowMessage('no a');
宁 宁柯 Unregistered / Unconfirmed GUEST, unregistred user! 2002-11-20 #6 假如这个字符串是 变量Str 那么 if Pos('a', Str) > 0 then begin ShowMessage('这个字符串里面有字符a'); end;