怎样将String型转化为char型(20分)

E

elfgirl

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• 2002-11-12

• #1

我想将1,2,3等数字赋给我下面的结构中的b,但是说类型不对,不能转化.我应该如何转化?[]
struct OldButton
{
char b[20];
};
OldButton Button[100];
for(int i=0;i<=10;i++)
{
strcpy(Button.b,IntToStr);
}

 

L

lynu

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• 2002-11-12

• #2

String的c_str()函数返回char *

 

H

hqlww

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• 2002-11-12

• #3

var
x:string;
n,i:integer;
p:char
begin
n:=length(x);
for i=1 to ndo
p:=x;
end;

 

E

elfgirl

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• 2002-11-12

• #4

出来错误信息如下,我包含了string.h文件,然后将上面的代码 IntToStr前面加上了c_str
[C++ Error] newworkflow1.cpp(500): E2268 Call to undefined function 'c_str'
[C++ Error] newworkflow1.cpp(500): E2335 Overloaded 'IntToStr' ambiguous in this context
[C++ Error] newworkflow1.cpp(500): E2062 Invalid indirection

 

E

elfgirl

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• 2002-11-12

• #5

不行,我是想把数字1,2,3转化为char型赋给结构中的变量

 

C

codecb

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• 2002-11-12

• #6

string.c_str()

 

E

elfgirl

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• 2002-11-12

• #7

我用了,IntToStr(i).c_str()
还是有错误,上面的后俩个错误

 

B

bigroute

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• 2002-11-12

• #8

StrPcopy

 

张

张无忌

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• 2002-11-12

• #9

var
pchar;
a:string;
a:='e3eee';
p:=@a[1];

 

E

elfgirl

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• 2002-11-12

• #10

大家好,能不能帮我改改最上面的那个源程序,我真的改不对了

 

B

bcppbuilder

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• 2002-11-12

• #11

看看这个：
struct OldButton
{
char b[20];
};
OldButton Button[100];
for(int i=0;i<=10;i++)
{
AnsiString ChaStr =IntToStr(i)+'/0';
StrCopy(Button.b,ChaStr.c_str());

 

E

elfgirl

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• 2002-11-12

• #12

谢谢大家,不过分值有限,只好精神上感谢大家了

 

E

elfgirl

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• 2002-11-12

• #13

谢谢各位的指教