Z
zjj12
Unregistered / Unconfirmed
GUEST, unregistred user!
类型转换：怎样把一个16进制的字串转换为byte[],请各位大侠帮忙
B
Bxch_1000
Unregistered / Unconfirmed
GUEST, unregistred user!
把问题说清楚一点？
是'0A0B0C'转为[10][11][12]呢?
还是'0A0B0C'转为[67][68][69]呀?
是'0A0B0C'转为[10][11][12]呢?
还是'0A0B0C'转为[67][68][69]呀?
Z
zw84611
Unregistered / Unconfirmed
GUEST, unregistred user!
procedure WTB(dw: WORD;
var b: array of BYTE );
var
tdw: WORD;
begin
tdw := $00ff;
b[0] := (dw and (tdw shl 8))shr 8;
b[1] := (dw and tdw);
end;
你要求的字节顺序是怎样的？如果字是$1234，那么要求b[0]=$12,b[1]=$34，还是
b[0]=$34,b[1]=$12？
var b: array of BYTE );
var
tdw: WORD;
begin
tdw := $00ff;
b[0] := (dw and (tdw shl 8))shr 8;
b[1] := (dw and tdw);
end;
你要求的字节顺序是怎样的？如果字是$1234，那么要求b[0]=$12,b[1]=$34，还是
b[0]=$34,b[1]=$12？
X
xianjun
Unregistered / Unconfirmed
GUEST, unregistred user!
我想楼主的意思应该是：
procedure TForm1.Button1Click(Sender: TObject);
var
I: Integer;
HexStr: string;
ByteArray: array of Byte;
begin
HexStr := 'AD1E0F2EDEFEAAFF';
SetLength(ByteArray, Length(HexStr) div 2);
for I := 1 to Length(ByteArray)do
ByteArray[I - 1] := StrToInt('$' + HexStr[I*2 - 1] + HexStr[I*2]);
ShowMessage(IntToStr(Length(ByteArray)));
end;
[
][][]
procedure TForm1.Button1Click(Sender: TObject);
var
I: Integer;
HexStr: string;
ByteArray: array of Byte;
begin
HexStr := 'AD1E0F2EDEFEAAFF';
SetLength(ByteArray, Length(HexStr) div 2);
for I := 1 to Length(ByteArray)do
ByteArray[I - 1] := StrToInt('$' + HexStr[I*2 - 1] + HexStr[I*2]);
ShowMessage(IntToStr(Length(ByteArray)));
end;
[
][][]
J
jsxjd
Unregistered / Unconfirmed
GUEST, unregistred user!
问题不明，串有什么样的？
D
dedman
Unregistered / Unconfirmed
GUEST, unregistred user!
String s = "f334223a29f";
int len = (int)Math.ceil(s.length()/2.0);
byte[] bs = new byte[len];
for(int index =0;
index < len;
index++){
int endIndex = ((index*2+2)>s.length())?s.length():index*2+2;
bs[index] = (byte)Integer.parseInt(s.substring(index*2,endIndex),16);
for(int i = 0;
i< bs.length;
i++)
System.out.println(""+bs);
output:
-13,52,34,58,41,15
satisfy your requirement?
int len = (int)Math.ceil(s.length()/2.0);
byte[] bs = new byte[len];
for(int index =0;
index < len;
index++){
int endIndex = ((index*2+2)>s.length())?s.length():index*2+2;
bs[index] = (byte)Integer.parseInt(s.substring(index*2,endIndex),16);
for(int i = 0;
i< bs.length;
i++)
System.out.println(""+bs);
output:
-13,52,34,58,41,15
satisfy your requirement?
Z
zjj12
Unregistered / Unconfirmed
GUEST, unregistred user!
各位大侠，我是把一个字符串使用getBytes()转换为byte[]，
再使用Integer.toHexString（）把byte[]中得byte转换为String 输出的；
现在返回来输出。该怎么办？
再使用Integer.toHexString（）把byte[]中得byte转换为String 输出的；
现在返回来输出。该怎么办？