copyfile就可以了,自己看帮助,无非就是变了个名字
或者
Procedure FileCopy( Const sourcefilename, targetfilename: String );
Var
S, T: TFileStream;
Begin
S := TFileStream.Create( sourcefilename, fmOpenRead );
try
T := TFileStream.Create( targetfilename,
fmOpenWrite or fmCreate );
try
T.CopyFrom(S, S.Size ) ;
finally
T.Free;
end;
finally
S.Free;
end;
End;
{This way uses memory blocks for read/write.}
procedure FileCopy(const FromFile, ToFile: string);
var
FromF, ToF: file;
NumRead, NumWritten: Word;
Buf: array[1..2048] of Char;
begin
AssignFile(FromF, FromFile);
Reset(FromF, 1); { Record size = 1 }
AssignFile(ToF, ToFile); { Open output file }
Rewrite(ToF, 1); { Record size = 1 }
repeat
BlockRead(FromF, Buf, SizeOf(Buf), NumRead);
BlockWrite(ToF, Buf, NumRead, NumWritten);
until (NumRead = 0) or (NumWritten <> NumRead);
CloseFile(FromF);
CloseFile(ToF);
end;