c和delphi类型转换(50分)

如何将C中的结构转化为DELPHI中的 RECORD(类型）？
typedef unsigned char dpl_uint8_t;
typedef unsigned short dpl_uint16_t;
typedef unsigned int dpl_uint32_t;
typedef signed char dpl_int8_t;
typedef signed short dpl_int16_t;
typedef signed int dpl_int32_t;
struct cmppe_login{
char id[12];
char auth[12];
dpl_uint8_t type;
dpl_uint8_t version;
dpl_uint32_t timestamp;
}

这个如何？
type
dpl_uint8_t = Byte;
dpl_uint16_t = Word;
dpl_uint32_t = Word;
dpl_int8_t = Char;
dpl_int16_t = SmallInt;
dpl_int32_t = Integer;

type
cmppe_login = record
id: Array[0..11] of Char;{试验一下11或者12}
auth: Array[0..11] of Char;
type: DPL_UINT8_T;
version: DPL_UINT8_T;
timestamp: DPL_UINT32_T;
end {cmppe_login};

type
dpl_uint8_t=byte;
dpl_uint16_t=word;
dpl_uint32_t=Cardinal;
dpl_int8_t=shortint;
dpl_int16_t=smallint;
dpl_int32_t=integer;
type
cmppe_login=record
id:array [0..11] of char;
auth:array [0..11] of char;
ctype:dpl_uint8_t;
version:dpl_uint8_t;
timestamp:dpl_uint32_t;
end;

接受答案了.

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失去了一种公平的环境，没有起码的对人的尊重……